Cost accounting
This query is : Resolved
12 August 2012
how to calculate this:
( 1+.12)^365 ..is there any other method of calculating it.
( 1+.12)^365 ..is there any other method of calculating it.
13 August 2012
Use log/antilog to solve it.
log x = 365 log (1.12)
solve it.
log x = 365 log (1.12)
solve it.
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