Urgently solve

1.S.i.= (P* 10*2)/100

c.i.= q(1+5/100)^2 - q

S.i.=c.i.

p/5=q(21/20)(21/20)-q

p/5=q*441/400-q

   =q(441-400)/400

p   =q * 41*5/400

p=q*41/80

2.prob of getting white ball from urn 1 = 3/5 and simaltaneously getting a white ball from seconf wrn is 5/11

Prob of gettingblack ball from urn 1 = 2/5 and simaltaneously getting a white ball from seconf wrn is 4/11

therefore, total prob of getting a white ball is= (3/5 * 5/11) +(2/5 * 4/11)  =  23/55

3.Prob of getting white ball from bag 1 = 3/8 and getting a white ball from seconf bag is 4/6

prob of getting both white ball = 3/8 * 4/6 = 1/4

4..Prob of getting 1st green ball from bag =m/9+m,

Prob of getting 2nd green ball from bag =m-1 / 9+m-1,  

total prob = (m/9+m)*(m-1 / 9+m-1)=1/7 (given)

solving the equation m=6 or -2

as it cant be -2, correct ans is 6

5.prop of atleast one getting scholarship =1- prob of none getting scholarship

prob of a girl child not getting scholarship=.4(1-.6)

prob of  a boy child not getting scholarship= .2(1-.8)

prob od none getting a scholarship= .4*.2=.08

prop of atleast one getting scholarship =1- .08 = .92