Solve please

1406 views 11 replies

1).given observations 4,9,11,14,37 mean deviation about median is

a).11,                  b).8.5,                   c).7,                     d).4.75.

2).if X ~ n(3,36) & Y~ N(5,64) then X + Y ~ (8,A).the value of A is

a)100,                     b).10,                          c).64,                            d).36.

Replies (11)

Q1 ANS- A,11

Q2 ANS- A,100

clarify the answer please........................................

QNO-1= MEDIAN=(N+1)/2TH TERM IS MEDIAN=(5+1)/2=3RD TERM IS MEDIAN,WHICH IS 11. ans

QNO-2=X+Y THEN ALLVARIABLE WILL BE IN SUM=E.G 3+5=8 AS IT IS 36+64=100 ans

2nd question i can't understand..

VARIABLES OF X= (3,36)

VARIABLES OF Y = (5,64)

X+Y=SUM OF VARIABLES

X+Y=3+5 & 36+64=(8,100)

100 IS VALUE OF A

 

ok 2nd question i understand but 1st question is mean deviation about median.

is answe for first ques is 7.6 exactly

please clarify the answer

median is 11

4-11= 7 ( ignoring -ve sign)

9-11=2

11-11 =0

14-11=3

37-11 = 26

 now take simple average of (7+2+0+3+26)/5 = 7.6 

tell ... is answer ryt

yes.answer is 7.

7.6 is the right answer

 


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