See 

suppose the eq. is

log y=log 10-0.322*log 30

log y= 1 - 0.322*(1.4771)[explantion:- now here count the no before decimal as in first part it is 10 two digit so u  ll write 1as there value of 10 in log table is 0 so tehe will be no value after 10 &  in the second part vlue is 30 that is also two digit so we have written 1i.e. (jitne bhi digit ho usme se ek kam kar ke likhte hai) here we will see value of 30 in log table i.e. 4771 we will write this after decimal(see 30 in column 0 in log table).

log y=0.5244(simlpe clculation of right hand side)

y = antilog(0.5244) (log jab  = ke other side jayega to anti log ho jayega)

y=3.345[Explanation:- no of digit after decimal is 4 so we will write 3(i.e. 4-1) put a decimal sign n see the value of .52 in coloumn 4 then add to this value mean diffrence of 4 in the same row )

hope you understand my language 

See
suppose the eq. is

log y=log 10-0.322*log 30

log y= 1 - 0.322*(1.4771)

[explantion:- now here count the no before decimal as in first part it is 10 two digit so u ll write 1after this see value of  10 in  0 column in log table as the value of 10 in log table is 0 so there will be no value after 1 & in the second part value is 30 that is also two digit so we have written 1i.e. (jitne bhi digit ho usme se ek kam kar ke likhte hai) now  we will see value of 30 in log table i.e. 4771 we will write this after decimal(see 30 in column 0 in log table).

log y=0.5244(simlpe clculation of right hand side)

y = antilog(0.5244)  (log jab = ke other side jayega to anti log ho jayega)

y=3.345

[ Explanation:- no of digit after decimal is 4 so we will write 3(i.e. 4-1) put a decimal sign n see the value of .52 in coloumn 4 then add to this value mean diffrence of 4 in the same row )

hope you understand my language

Thanks a ton pooja...............you saved me..........once again thanks a lot..................I owe this to you...........

Thanx 

CAN U EXPLAIN for numbers having les than 2 digits -    .035/.35/3

then u dnt hv to see the mean difference just see the value in 0

thnx pooja

Anytime........

Sincere thanks for keeping the good work going Pooja Ji.........helping others generously .............:)

I don't why but "Thank user" tab is not working now,

Anyways thanks for the explanation,You explained it very well,Just starting Learning Curve

Originally posted by : Shah Tarun
	I don't why but "Thank user" tab is not working now, Anyways thanks for the explanation,You explained it very well,Just starting Learning Curve

Oh u already thanked me twice its more more more den enough..........all d best

hey pooja cn u giv me some suggestion regarding the other reference books avaliable in market for final Books

If u r asking for OR den i read PADUKA n fr me its best..........rest i m not assured of................