Two train of same length cross a pole in 4min & 5min respectively.
in how much time they will cross each other if they approach each other from opposite direction(i.e face to face)..
give answer with working...
CA,CMA,CS Karan Gogia (Employed) (230 Points)
17 June 2011
Two train of same length cross a pole in 4min & 5min respectively.
in how much time they will cross each other if they approach each other from opposite direction(i.e face to face)..
give answer with working...
buddy
(-)
(71 Points)
Replied 17 June 2011
let 4min train = A
let 5 min train = B
Train A crosses a pole in 4 min
Train B in 5 mins which means this train is 60 secs late and i.e. it is late by 15 secs for every on min of train A
(60 secs /4min = 15 secs per min of A)
when they come HEAD TO HEAD
FACTOR = Train A will be 0.8 times faster to Train B [i.e 60 secs / 75 secs = 0.8 times]
Divide this factor to any time value of A & Multiply this factor to time value of B to get your answer
In above question - To Reach the POLE HEAD TO HEAD = A will take 5 mins to reach train B
{ WORKING ANS = 5 mins given by (4mins of A) DIVIDED BY (0.8 factor) }
CA,CMA,CS Karan Gogia
(Employed)
(230 Points)
Replied 17 June 2011
gud effort..but u did random work...n train A is not 0.8times fater than B..it takes 0.8 time of wat time B take....
try again n give the final result....
MaNThaN Shah
(Student)
(315 Points)
Replied 20 June 2011
Ca Final Student
(NA)
(45 Points)
Replied 20 June 2011
Let distance be x for both. Then speeds are x/4 and x/5 respectively. Distance that needs to be covered is 2x. Speed is (x/4 plus x/5). Solving, 2x/(x/4 + x/5), we get 4.44 minutes.
CA,CMA,CS Karan Gogia
(Employed)
(230 Points)
Replied 20 June 2011
CA final student....very good working and u got the rite ans...congrats
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