Break it if u can???

Others 758 views 5 replies

 

Two train of same length cross a pole in 4min & 5min respectively.

in how much time they will cross each other if they approach each other from opposite direction(i.e face to face)..

give answer with working...

Replies (5)

let 4min train = A

let 5 min train = B

Train A crosses a pole in 4 min

Train B in 5 mins which means this train is 60 secs late and i.e. it is late by 15 secs for every on min of train A

(60 secs /4min = 15 secs per min of A)

when they come HEAD TO HEAD

FACTOR = Train A will be 0.8 times faster to Train B [i.e 60 secs / 75 secs = 0.8 times]

Divide this factor to any time value of A & Multiply this factor to time value of B to get your answer

In above question - To Reach the POLE HEAD TO HEAD = A will take 5 mins to reach train B

{ WORKING ANS = 5 mins given by (4mins of A) DIVIDED BY (0.8 factor) }

gud effort..but u did random work...n train A is not 0.8times fater than B..it takes 0.8 time of wat time B take....

try again n give the final result....

TRAIN A is 1.25 times faster than train B. . .Total time of 4 min/2.25 = 1.77 min ans

Let distance be x for both. Then speeds are x/4 and x/5 respectively. Distance that needs to be covered is 2x. Speed is (x/4 plus x/5). Solving, 2x/(x/4 + x/5), we get 4.44 minutes.

CA final student....very good working and u got the rite ans...congrats


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