Please solve this (cpt maths- equations)

can someone pls. help me with these question.

as far as sum no. 92 is concerned, i substituted x=300, 900 and y=6800, 10400 respectively and got option c as the correct answer. (correct me if the method is wrong)

However, I am unable to solve the next 3 questions.

Replies (2)

92. variable cost=(10400-6800)/(900-300) = 6

now, 6800=6*300+fixed cost

so fixed cost= 5000

eq : y=6x+5000

 

93. at break even point profit = 0 ie contribuion=fixed cost

so, break even point = fixed cost/contribution

=5000/(8-6) = 2500

 

94. if profit of 2000 req,

break even point=fixed cost+req profit/contribution

=5000+2000/(8-6) = 3500

 

95. by above formula

=5000-3000/(8-6)=1000

hope its clear...feel free to ask if prblm persists...

thank you very much!!!!!

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