1).if one roots of 5x^2+13x+p be reciprocal of the other then the value of p is
a).-5, b).5, c).1/5, d).-1/5.
2).the number of diagonals in a decagon is
a).30, b).35, c).45, d).none.
3).if n,p,q are in g.p then the expression for p in terms of n & q is-------
a).n/q, b).(nq)^1/2, c).q^2n, d).nq.
1. Product of the roots = c/a= 1
So,
p/5= 1
p= 5
3. (nq)^1/2
please clarify question no.3
and question no.2 also.........................
n,p,q are in GP
So common ratio is same fr all consecutive terms..
So,
p/n= q/p
p^2= nq
p= (nq)^1/2
Are there was some formula for q.2 ... i am unable to recall it at the moment...I will revert if i get the answer...
U can ask me any doubt u have in CPT...
Q.2 No of Diagonals of a polygon = n(n-3)/2, n=no of sides
And ur decagone has 10 sides
So No of diagonals=10(10-3)/2=35
Mono = 1
Di = 2
Tri = 3
Tetra = 4
Penta = 5
Hecza = 6
Hepta = 7
Octa = 8
Nena = 9
Deca = 10
CAclubindia
