Can anyone help me to solve this

CPT 1080 views 9 replies

Dear CCI members plz help me to solve these problems from Central Tendency, I got these questions from Masterminds book

1. The Average age of 15 students is 15 years. out of these the average age of 5 students is 14 years and that of other 9 students is 6 years, then the age of 15th student is ....

a) 11 years  b) 14 years  c) 15 years d) None

2. The Average of a group of 10 students is 20 years, if average age is increased by 2 years when two new students are joined then the average age of two new students is ....

a) 84   b) 64   c) 32   d) 42

3. The average of 5 quantities is 6 and in which the average of 3 is 8. what is the average of the remaining two?

   a) 4     b) 5     c) 3    d) 305

Replies (9)
1- d i.e. None 2- c i.e. 32 years 3- c i.e. 3
1 - d, 2 - c, 3 - c
Agree with Rishi...

Thank you soo much for your replies friends. Can you plz explain me how can i solve this problem. Coz i dont know the method to solve this. plz help me by solving this step wise.

First multiply all the averages with their respective numbers. Then add both the products of 5 students and 9 students and deduct it from the product of 15 students 15*15 - (5*14+9*6)
2. average of 10 studnts- 20 avg of 12 studnts- 22 total age of 10 stdnts- 10*20=200 total age of 12 stdnts- 12*22=264 total age of 2 new stdnts = 264-200= 64 Avg age of 2 new stdnts = 64/2=32
3. Total of 5 qts- 5*6=30 total of 3 qts- 3*8=24 total of remaining 2 qts- 30-24=6 avg of rem. Two = 6/2= 3

Study  any school book of  Arithmatic for 'Averages' problems .

Prabhakar sir thanks for your advice.....But in our state we dont have statistics subject at school level. It will be introduced at graduation level. thats why m getting problem to solve problems from this subject.


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