Following are two normal equations obtained for deriving the regression line of y and x:
5a + 10b = 40
10a + 25b = 95
the regression line of y on x is giveb by:
a) 2x + 3y + = 5
b) 2y + 3x + = 5
c) y = 2 + 3x
c) y = 3 + 5x
Following are two normal equations obtained for deriving the regression line of y and x:
5a + 10b = 40
10a + 25b = 95
the regression line of y on x is giveb by:
a) 2x + 3y + = 5
b) 2y + 3x + = 5
c) y = 2 + 3x
c) y = 3 + 5x
We need to solve the two normal equations to get the value of 'a' (y intercept) & 'b' (slope) of the regression line y on x.
5a + 10b = 40 Multiply the eqn. by 2 & solve
10a + 25b = 95
10a + 20b = 80
so 'b' = 3 & 'a' = 2
The equation would be Y = 2 + 3X
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