Pl give formula for this prolem

CPT 684 views 1 replies

A straight line ‘L’ is ⊥lr to the line 2x + y – 4 = 0


and cuts x-axis at (3,0), find the ⊥lr distance


from the point (2,-3) to the line ‘L’


a)1/root5

b).5

c).root 5

d).2root5

 

Replies (1)

Given Equation of the line 2X+Y-4=0

Slope= -2

For perpendicular lines, Product of Slopes must be equal to '-1'

So the Slope of Perpendicular line = 1/2

Let the equation be X-2Y+K=0

As this line passes through point (3,0)

3-0+k=0

Therefore k=-3

The equation of perpendicular line is X-2y-3=0

The Perpendicular distance from the point(2,-3) = Absol(2-(2*(-3)-3)/(1^2+2^2)^-2

=5^-2

Therefore option C i.e 'root 5' is correct


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