A straight line ‘L’ is ⊥lr to the line 2x + y – 4 = 0
and cuts x-axis at (3,0), find the ⊥lr distance
from the point (2,-3) to the line ‘L’
a)1/root5
b).5
c).root 5
d).2root5
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Pl give formula for this prolem
Replies (1)
Given Equation of the line 2X+Y-4=0
Slope= -2
For perpendicular lines, Product of Slopes must be equal to '-1'
So the Slope of Perpendicular line = 1/2
Let the equation be X-2Y+K=0
As this line passes through point (3,0)
3-0+k=0
Therefore k=-3
The equation of perpendicular line is X-2y-3=0
The Perpendicular distance from the point(2,-3) = Absol(2-(2*(-3)-3)/(1^2+2^2)^-2
=5^-2
Therefore option C i.e 'root 5' is correct
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