Permutation problem

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Q1The number of ways in which 7boys sit in a round table so that two particular boys may sit together is

A]240

B]200

C]120

D]none of these

Q2 The number of arrangement of 10 different thing taken 4 at atime in which one particular thing always occur

Explain abovetwo  through giving their solution.

 

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On 23 February 2012 at 12:54 Report
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775 Points Posted on 23 February 2012
1. See the formula to find no. Of persons to be seated on round table is (n-1)!. Here , any two persons should always sit together , so consider these two as one object , so we are left with 7-1 = 6 objects. Now according to formula we have (6-1)! = 120.
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On 23 February 2012 at 22:56
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775 Points Posted on 23 February 2012
2. The formula to find out no. Of permutations /arrangements when any one object is always included is (n-1)P(r-1).. Here n=10 , r=4.. So we have 9P3=9!/(9-3)!=504
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On 23 February 2012 at 23:03
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Posted on 24 February 2012

anwer given in module for 1st and 2nd question are as follow

Q1 240

Q2 2016

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On 24 February 2012 at 10:51
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Student
775 Points Posted on 25 February 2012
For 1. See we got 120 . Now the two boys themselves can sit in 2! Ways so we have 120 * 2 = 240.
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On 25 February 2012 at 10:20

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