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one doubt

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117 Points Posted on 09 October 2018
the integration of log x DX=
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On 09 October 2018 at 10:43 Report
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hyderabad
1653 Points Posted on 09 October 2018
x (log x -1) + c
where c is constant
9 Reply
On 09 October 2018 at 11:53
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117 Points Posted on 09 October 2018
explain the answer please
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On 09 October 2018 at 12:24
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hyderabad
1653 Points Posted on 09 October 2018
Let ∫logxdx=∫(logx*1)dx
(* is multiplication)
Now, by using formula

∫uvdx=u∫vdx-∫[du/dx*∫vdx]dx

Let u=logx and v=1

∫logxdx=logx∫dx-∫[d/dx(logx)*∫dx]dx

=logx*x-∫(1/x*x)dx

=xlogx-∫dx
=xlogx-x+C
=x(log -1) +c
9 Reply
On 09 October 2018 at 13:38
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as an article
951 Points Posted on 09 October 2018
above answer is crct
10 Reply
On 09 October 2018 at 16:27


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