Maths plz solve

1. 3 ladies and 3 gents can b seated at round table so tht any two and only two of the ladies sit together.the number of ways is
  
a.70 b.27 c.72 d.none
2. at an election ther are 5 candidates and 3 membrs are to b electd. A voter is entitled to vote for any number of candidates not greater than the number to be electd. The number of ways a voter cn choose to vote is

a.20  b.22  c.25  d.None 

 

Replies (2)

c. 72

& C.25

2. A voter can vote for none leaving the paper blank or kecan vote for one person or two or three

i.e. 5c0+5c1+5c2+5c3

= 1+5+10+10

=26

so answer is none.

1.we can choose the two ladies to be seated together in 3c2 i.e 3 ways. now they can be seated together in 2 ways. let us consider them to be an entity called X. Now only men can sit beside X. they can be choosen in 3c2 ways i.e 3 ways. now the selected two men can sit in two ways (they will result in clockwise and anticlockwise ways of arrangement on the table). Now the remaing two  can sit in two ways therefore it is 3X2X3X2X2=72 therefore answer is 72

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