average age of a group of 10 students is 20 years,if average age increased by two years when two new students are joined then the average age of two new students
a).84 b).64
c).32 d).42
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Replies (19)
(C) is correct option
.32 i guess
What's the correct answer by the way?
32 is the Correct Answer......
kindly doing my sum immediately....
how this answer is 32?
See total Age of 10 Students = 10 Students * 20 Years = 200
New Average = 20 Years + 2 Years = 22 Years
Total Age of 12 Students = 12(10+2) Students * 22 Years = 264
Total age of the 2 new students = 264 - 200 = 64
Avg age of the new students = 64 / 2 = 32 years
correctly said above
if x is inversely related with square of y for x =1 & y=2 then find the value of x when y=6 :
a).3 b).9
c).1/3 d).1/9
X = 9
as x = 1/y2 and the retio of x : y comes out to be 1 : 1/4 i.e 4 : 1
if we put y = 6, then x = 1/36 and ratio is 4: 1
from where x comes out to be 9.
C) Thirty Two 32 !!
Solution is correct...........
The answer of your first question is c.) 32
And of other is b.) 9
| Originally posted by : !..SaNKeT..! | ||
 |
See total Age of 10 Students = 10 Students * 20 Years = 200 New Average = 20 Years + 2 Years = 22 Years Total Age of 12 Students = 12(10+2) Students * 22 Years = 264 Total age of the 2 new students = 264 - 200 = 64 Avg age of the new students = 64 / 2 = 32 years |
 |
if p & q are roots of x^2-bx+c=0then the equation whose roots are (pq+p+q) & (pq-p-q) is :
a).x^2-2cx+c^2-b^2=0
b).x^2-2bx+c^2+b^2=0
c).cx^2-2(b+c)x+c^2=0
d).x^2+2bx-(c^2-b^2)=0
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