Kindly solve

CA 1278 views 19 replies

average age of a group of 10 students is 20 years,if average age increased by two years when two new students are joined then the average age of two new students

a).84                                                                                                                                                                   b).64

c).32                                                                                                                                                                    d).42

 

Replies (19)

(C) is correct option 

.32 i guess

What's the correct answer by the way?

32 is the Correct Answer......

kindly doing my sum immediately....

how this answer is 32?

See total Age of 10 Students = 10 Students * 20 Years = 200

New Average = 20 Years + 2 Years = 22 Years

Total Age of 12 Students = 12(10+2) Students * 22 Years = 264

Total age of the 2 new students = 264 - 200 = 64


Avg age of the new students = 64 / 2 = 32 years

correctly said above

if x is inversely related with square of y for x =1 & y=2 then find the value of x when y=6 :

a).3                                                                                                                                                                  b).9

c).1/3                                                                                                                                                                d).1/9

 

X = 9 

as x = 1/y2  and  the retio of x : y comes out to be 1 : 1/4 i.e 4 : 1

if we put y = 6, then x = 1/36 and ratio is 4: 1

from where x comes out to be 9. 

C) Thirty Two 32 !!

Solution is correct...........

The answer of your first question is c.) 32

 

And of other is b.) 9

Originally posted by : !..SaNKeT..!

See total Age of 10 Students = 10 Students * 20 Years = 200

New Average = 20 Years + 2 Years = 22 Years

Total Age of 12 Students = 12(10+2) Students * 22 Years = 264

Total age of the 2 new students = 264 - 200 = 64


Avg age of the new students = 64 / 2 = 32 years

if p & q are roots of x^2-bx+c=0then the equation whose roots are (pq+p+q) & (pq-p-q) is :

a).x^2-2cx+c^2-b^2=0

b).x^2-2bx+c^2+b^2=0

c).cx^2-2(b+c)x+c^2=0

d).x^2+2bx-(c^2-b^2)=0

 


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