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a is equal to b.
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1 = 1 a = b
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Adding a2 and b2 … Since a2= b2 both sides of equation |
a2+b2 = b2+b2
a2+b2 = 2b2
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Subtracting 2 a2A From both sides
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a2+b2-2a2 = 2b2-2a2
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Solving Cutting (b2- a2 )on both sides |
(b2- a2 )= 2(b2- a2)
1 = 2
a not equal to b
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This is a contradiction to a = b
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if a =b then a-b =0 and you cannot cancel 0 on both sides because 0*1 = 0*2 = 0*3 = .. =0 that is the mistake
Tejaswiji... your answer is correct.. but the explanation is as follows.
Answer to the problem:
In order to cancel the terms (b2- a2 ) on both sides, we have to divide (b2- a2 ) on RHS and LHS.
which means we have to divide 0 from RHS and LHS.
DIVISION BY ZERO IS NOWHERE POSSIBLE!!
THAT IS THE MISTAKE.
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