A real problem which make me mad

Based on 4 + 5 = 9

                   5 + 4= 21

6 + 9 = 15

9 + 6 = 75

how did u get the answer ? can anyone explain, according to me it should me 15 and 45.

Typically tough q for me ...

koi easy tarika ho to muje bi bata dena

Check this out....

4+5=9

5+4=21 [its 5+(4*4)] this is the actual logic..

Similarly,

6+9=15 &

9+6=45 [9+(6*6)]

Originally posted by : nikhil jain
	Check this out.... 4+5=9 5+4=21 [its 5+(4*4)] this is the actual logic.. Similarly, 6+9=15 & 9+6=45 [9+(6*6)]

Hi Nikhil, there is a problem with ur logic. It cant be applied to 4+5=9. If u do, u will get 29 & not 9. Whatever logic u apply, u have to apply it to both the cases,i.e.both 4+5=9 as well as 5+4=21. I can also say (5*5)-4=21 and use the same method to get 9+6=75[(9*9)-6]. But thats not the correct way..  

Originally posted by : *RENU SINGH *
	Typically tough q for me ... koi easy tarika ho to muje bi bata dena

Well it is actually very easy. I think the way I explained made it appear tough. U just write down the equations as below:

4+(1+4)=9

(1+4)+4=21

Multiply 2^nd digit by 3^rd digit & add the resultant figure to 1^st & 2^nd digits(as below)

(1*4)+4+1=9=RHS

(4*4)+1+4=21=RHS

Now lets compute 6+9 using the same logic..

6+(1+8)=(1*8)+6+1=15

Now lets find out 9+6

(1+8)+6=(8*6)+1+8=57

Hope its clear now