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three jug problem

Others 1066 views 6 replies

I have three jug whose capacity are 8 lt.,5 lt. and 3 lt. and no one jug is calibrated then how can I divide 8 lt. water in two equal parts.

Replies (6)

Its simple yaar..just try.

If you need a hint than tell me...

Need a hint!!!

the procedure to divide the water equally is

Jug     8     5     3

Water -      5      3

           3      5      -

           3       2    3

           6       2    -

           6       -     2

            1     5      2

            1      4     3

             4      4

Excellent affords..you can make it simple.


 

Jug      8 L          5 L            3 L


Steps

01       8  0  0


02  3  5  0


03  3  2  3


04  6  2  0


05  6  0  2


06  1  5  2


07  1  4  3


08  4  4  0

good job...Now try for Chess board?  you wil find it Interesting.


CCI Pro

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