Player!! puzzle that rocks 3!!

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IT IS ILLEGAL TO CARRY ANYTHING WHICH IS LONGER THAN 400 CENTIMETRE IN THE CITY BUS OF SCAMVALLEY?

A PROFESSOR WANTS TO CARRY A RARE METAL ROD OF LENGTH 5 METRE WITHOUT CUTTING THE ROD INTO SMALL PIECES.

IS THERE ANYWAY THE PROFESSOR COULD CARRY THE ROD WITHOUT CUTTING IT?

(GUYS HE DID IT.. BUT HOW)

Replies (21)

Since he is a Professor, he could say that he is carrying the metal rod for his Research......smiley

He would have put the rod on top of the bus.

turn it into a circle as a circle has no length no contravention of any law...

NOT YET THE ANSWER!!!

PROFESSOR IS NOT READY TO TAMPER WITH THE ROD.

anything longer cannot be carried but anything having widtth more than 400 can be carried

 

so he would carry it that ways....

he carried it keeping in vertical position so that lenght would be no problem.

 

He would enter into a Scam in ScamValley and put the rod on top of the bus.

Rather, he would not go on a bus and take the rod in a taxi or his car.

If it cant be cut then possibly he can mould it to 180 degrees from centre by heating...Hence reducing length to half i.e. 250cms...

When He would reach his destination again by regeating he can get the original shape...

Yes, he will carry it in vertical posisition, so length becomes widtth & widtth becomes length.then restrictions go last!

Can an attachment be made to the bus???

If possible then He can put about 400 cms of the rod in bus and additional in some attachment like an extra wagon or a bogey or any vehicle...

 

As it is a city bus,may be the professor adjusted it as a handle in d bus,to be hold by the persons who are standing.

Originally posted by : M.Varalakshmi

As it is a city bus,may be the professor adjusted it as a handle in d bus,to be hold by the persons who are standing.


Good one...

don't knw ...

bt i guess he wil bend it ....

OKAY GUYS.... I WILL GIVE YOU THE ANSWER...

HERE IT IS

THE PROFESSOR WILL CARRY THE METAL ROD IN A BOX WITH LENGTH 4 METER AND BREADTH 3 METER AND THE ROD WILL BE KEPT DIAGONNALLY (SEE FIGURE)

I HOPE YOU REMEMBER THE EQN

LENGTH2 + BREADTH2 = HYPOTUNUSE2

 

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