I challenge you are not a genius

Others 2850 views 43 replies
As a riddle, the answer is zero legs on the bus since the bus has wheels instead of legs.

But as a maths problem; It's not a tricked question -- just a straightforward maths problem

Confirmed answer is 10990 legs.

§ Let's say the whole situation simply :
- There are 7 girls.
- Each girl has 7 backpack
- Each backpack has 7 big cats
- Each big cat has 7 little small cats.
§ Question: How many legs are there in the bus?
§ Let's focus on each part of the question systematically, write down on a piece of paper if you have to, following my steps of chains.

 


1. Focus on the first girl first:
A B C D E F G
Girl A has 7 backpacks



 


2. Now focus on first backpack A1 :
A1 A2 A3 A4 A5 A6 A7
Backpack A1 has 7 big cats



 



3. Now focus on first big cat :
1 2 3 4 5 6 7

Ø Each big cats have 7 small cats (that's the end of the focus)
Systematically, 7 small cats has 28 legs (7 * 4) combined with the big cat that owns this 7 small cats.

Let's call this the "cat chain", so cat chain 1 has 32 legs altogether.
Ø So since there are 7 big cats
7 * 32 = 224 legs

Ø Therefore each backpack has 224 legs

Ø Finally, each girl has 7 * 224 = 1568 legs.

 


Lastly, since there are 7 girls, A to G, there are 7 * 1568 legs (per girl) = 10976 legs.

Now, since each girl also has 2 legs each;
SO, (7 * 2) + 10976 = 10990 legs altogether

Note: Disregarding bus driver, buses and etc…Only focus on the girl and their backpacks!

Replies (43)
As a riddle, the answer is zero legs on the bus since the bus has wheels instead of legs.

But as a maths problem; It's not a tricked question -- just a straightforward maths problem

Confirmed answer is 10990 legs.

§ Let's say the whole situation simply :
- There are 7 girls.
- Each girl has 7 backpack
- Each backpack has 7 big cats
- Each big cat has 7 little small cats.
§ Question: How many legs are there in the bus?
§ Let's focus on each part of the question systematically, write down on a piece of paper if you have to, following my steps of chains.

 


1. Focus on the first girl first:
A B C D E F G
Girl A has 7 backpacks



 


2. Now focus on first backpack A1 :
A1 A2 A3 A4 A5 A6 A7
Backpack A1 has 7 big cats



 



3. Now focus on first big cat :
1 2 3 4 5 6 7

Ø Each big cats have 7 small cats (that's the end of the focus)
Systematically, 7 small cats has 28 legs (7 * 4) combined with the big cat that owns this 7 small cats.

Let's call this the "cat chain", so cat chain 1 has 32 legs altogether.
Ø So since there are 7 big cats
7 * 32 = 224 legs

Ø Therefore each backpack has 224 legs

Ø Finally, each girl has 7 * 224 = 1568 legs.

 


Lastly, since there are 7 girls, A to G, there are 7 * 1568 legs (per girl) = 10976 legs.

Now, since each girl also has 2 legs each;
SO, (7 * 2) + 10976 = 10990 legs altogether

Note: Disregarding bus driver, buses and etc…Only focus on the girl and their backpacks!

Originally posted by : Vishwas V Rao

It was pretty easy got it in the 1st attempt. But guess the answer is wrong because you forgot 2 legs of the driver. Else mention it as a bus which is not moving :p


question is what it is. you are not supposed to add a driver. bus is stationary or not is not a matter of question. you could have add a conductor or helper also.

 

nice finding, mr. rao. (1 bonus point for you) wink

Nice one. Thanx for sharing.... Keep sharingsmiley

 

Answer is 10990 legs

 

Girls                                   7 * 2 = 14 legs

Big Cats        7*7*7 = 343 * 4 = 1372 legs

Small Cats  7*7*7*7 = 2401*4 = 9604 legs

Total legs = 14+1372+9604 = 10990 legs

I Did, the answer is 10990

i also got it ................. n if u are talking about a bus driver how can u forget a conductor............lol

10990 legs

 

nice one!!

AND HOW ABOUT THIS:

/forum/some-logical-questions-test-your-brain-184083.asp

ALL THE BEST

nice one... got d answer... was able 2 open d the 1st file itself  which u uploaded...anyways thanx 4 sharing...smileyyes

nice one... got d answer... was able 2 open d the 1st file itself  which u uploaded...anyways thanx 4 sharing...smileyyes

Its Nt typical....i hv opened it in 1st shot...

...yes

 

thanks

i opened the sheet

 

Real Test Is This for the CA & CWA Community

 

A father, in his will, left his money to his children in the following manner:

 

  • Rs.1000 to the first born and 1/10 of what then remains, then
  • Rs. 2000 to the second born and 1/10 of what then remains, then
  • Rs. 3000 to the third born and 1/10 of what then remains,
  • and so on.

 

When this was done each child had the same amount.

 

How many children were there?

 

cheeky


CCI Pro

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