How can you prove 4=5.. Intersting and logical reply

Let us assume    -20 = -20

So    16-36 = 25-45

So    16-4*9 = 25-5*9

So    16-2*4*9/2 = 25-2*5*9/2

by adding 9/2 whole square both sides....

So    16-2*4*9/2+(9/2)² = 25-2*5*9/2+(9/2)²

But   {16-2*4*9/2+(9/2)²} is complete squaure of (4-9/2).

and {25-2*5*9/2+(9/2)²} is complete squaure of (5-9/2).

 

Therefor the equation is  (4-92)² = (5-9/2)²

By eliminating Square we will get (4-9/2) = (5-9/2)

Now by eliminating 9/2 from both sides we get  4  = 5 !!

Replies (3)

Can anyone find loofall in it !!!

LOOPHOLE IN THIS IS THAT


SQUARE ROOT CAN NOT BE ELIMINATED IN THIS WAY

IT SHOULD BE ELIMINATED USING +/-

I.E. (4-92)² = (5-9/2)²

By eliminating Square we will get EITHER (4-9/2) = (5-9/2)

OR (4-9/2) = -(5-9/2)

 

RESULT OF FIRST WILL BE 4=5 WHICH WILL BE FALSE

AND SECOND WILL RESULT THE SAME NUMBER ON BOTH SIDES

 Here is ur loofall {(16-2*4*9/2)+(9/2)²}

{(25-2*5*9/2)+(9/2)²}

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