CPT Ratio Problem - Pls help

Hii all please help me out in this problem of ratio and proportions

 

A box contains 56 in the form of coins of one rupee,50 paise,and 25 paise. the no. of 50 paise coin is double the no. of 25 paise coins and four time sthe no. of one rupee coins. the no of 50 paise coins in the box is

 

a)  64

b)  32

C)  16

d)  14

 

The answer is a) 64.......... pls tell how it is calulated with proper workings..

 

 

similar question

 

A bag contains187 in the form of 1 rupee , 50 paise  and 10 paise coins in ratio 3 : 4 : 5.. find the no. of each type of coins :

 

a) 102,136,170

B) 136,102,170

c) 170,102,136

d) none

 

 

the answer is A )............. even not getting this........... pls help me out in these problems......... thanks in advance....

 

Replies (4)

Let number of 50 paise coins = 4x

Let number of 25 paise coins = 2x

Let number of one rupee coins = x
 

Total amount = (0.5)(4x) + (0.25)(2x) + x = (2+0.5+1)x = 3.5x = 56 Rs. (given)

=> x = 56/3.5 = 16

Thus, number of 50 paise coins = 4x

                                                    = 4(16)

                                                     = 64

 

so, d ans. is A) 64.

Now 4 similar question ans....

 

Let number of one rupee coins = x

number of 50 paise coins = y

number of 10 paise coins = z
 

Given that x:y:z = 3:4:5

So, let x = 3m, y = 4m, z = 5m (i.e.where m is an integer.)

Total amount = 3m + (0.5)(4m) + (0.1)(5m) = 187

3m + 2m + 0.5m = 187

m(3+2+0.5) = 187

m = 187/5.5 = 34

Thus,

x = 3m = 102
y = 4m = 136
z = 5m = 170.

 

so, ans is A) 102:136:170.

Thanks very much bro for ur timely help........... god bless......

u mst welcome bro......:)

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