A straight line ‘L’ is ⊥lr to the line 2x + y – 4 = 0
and cuts x-axis at (3,0), find the ⊥lr distance
from the point (2,-3) to the line ‘L’
a)1/root5
b) 5 c) root5 d) 2 root5
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Replies (1)
Eqn Perpendicular to eqn 2x+y-3=0 is x-2y+A=0
Since eqn x-2y+A=0 pass through (cut x-axis) at (3,0),
3-0+A=0
A=-3
Therefore, the required eqn is x-2y-3=0
The perpendicular distance from (2,-3) to x-2y-3=0 is [|2+6-3|]/Sqrt(1+4)
Whis is = 5/Sqrt(5)=Sqrt(5)
Therefore answer is c.
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