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sfm oct 2018 pm Q57
guys how they computed values of N(0.5820) ?
Replies (1)
values of z are given as one tail values
we need to find body part i.e 1-tail value
now n(0.5820) is between 0.55 and 0.60 so look those values only
0.55 = 0.7088 (1- 0.2912)
0.60 = 0.7257 (1- 0.2743)
------------------------------
diff 0.05 = 0.0169
using interpolation, 0.7088 + 0.0169 / 0.05 * 0.032( 0.5820-0.55)
= 0.7197
we need to find body part i.e 1-tail value
now n(0.5820) is between 0.55 and 0.60 so look those values only
0.55 = 0.7088 (1- 0.2912)
0.60 = 0.7257 (1- 0.2743)
------------------------------
diff 0.05 = 0.0169
using interpolation, 0.7088 + 0.0169 / 0.05 * 0.032( 0.5820-0.55)
= 0.7197
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