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equations

Foundation / CPT 373 views 4 replies
The present age of a man is 8 years more than thrice the sum of the ages of his twi grandsons who are twins. after 8 years, his age will be 10 years more than twice of the sum of the ages of his grandsons. the age of the man when his grandson were born was.
a. 86 years
b. 73 years
c. 68 years
d. 63 years
Replies (4)

good question refer ca_cpt books  laugh

I got the answer, but i am not able to know the method how the answer came
let the present age of grandsons be x each.
so the present age = 8 + 3(2x) i.e (8+6x)
after 8 years.
8+6x+8 = 10+2[(x+8)2]
16+6x = 10+2[2x+16]
solving the above equation x=13.

So the present age of man =8+6x i.e. 86 Years
present age of grandsons =x=13.

so when grandsons were born age of man = 86-13 = 73 Years.
73 is the answer.

6X+8=age of man

6X+16=4X+32+10
X=13=grandson age

Age of man = 86

Age at the time of born of grandsons =86-13=73


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