The present age of a man is 8 years more than thrice the sum of the ages of his twi grandsons who are twins. after 8 years, his age will be 10 years more than twice of the sum of the ages of his grandsons. the age of the man when his grandson were born was.
a. 86 years
b. 73 years
c. 68 years
d. 63 years
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Replies (4)
good question refer ca_cpt books 
I got the answer, but i am not able to know the method how the answer came
let the present age of grandsons be x each.
so the present age = 8 + 3(2x) i.e (8+6x)
after 8 years.
8+6x+8 = 10+2[(x+8)2]
16+6x = 10+2[2x+16]
solving the above equation x=13.
So the present age of man =8+6x i.e. 86 Years
present age of grandsons =x=13.
so when grandsons were born age of man = 86-13 = 73 Years.
so the present age = 8 + 3(2x) i.e (8+6x)
after 8 years.
8+6x+8 = 10+2[(x+8)2]
16+6x = 10+2[2x+16]
solving the above equation x=13.
So the present age of man =8+6x i.e. 86 Years
present age of grandsons =x=13.
so when grandsons were born age of man = 86-13 = 73 Years.
73 is the answer.
6X+8=age of man
6X+16=4X+32+10
X=13=grandson age
Age of man = 86
Age at the time of born of grandsons =86-13=73
6X+8=age of man
6X+16=4X+32+10
X=13=grandson age
Age of man = 86
Age at the time of born of grandsons =86-13=73
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