A straight line ‘L’ is ⊥lr to the line 2x + y – 4 = 0
and cuts x-axis at (3,0), find the ⊥lr distance
from the point (2,-3) to the line ‘L’
a)1/root5
b).5
c).root 5
d).2root5
3 Replies
kumar
(Dy Mgr finance)
(24 Points)
Replied 19 April 2012
Ans : d) 2 / root 5
ABS ( ax+by+c) / Root (a^2+b^2)
kumar
(Dy Mgr finance)
(24 Points)
Replied 20 April 2012
2x+y-4=0
a=2,b=1,c=-4
x=3,y=0
Perpendicular distance = (abs(2*3+1*0-4))/Root(2^2+1^2)
= abs(6+0-4)/root (4+1)
=2/root(5)
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