Todays puzzle 11-11-2011

others 1733 views 7 replies

There is a casino and it has 4 gates (let’s name them as gate A, B, C and D). Every time you come inside the casino, you have to pay $5 and every time you leave the casino, you again have to pay $5. Also know that, whatever amount of money you carry with you inside the casino, it doubles.

For example if you carry $5, it will become $10. You have to go inside the casino through gate A, come out of B, again go inside the casino through gate C and finally come out of gate D. Now, how much money should you carry inside the casino so that when you finally come out of the gate D, you should be left with no (zero amount) money?

Comment if you know the answer

Solution of Todays Puzzle 10-11-2011

Replies (7)

Manas

CA Final

43 Points Joined February 2011

its $11.25 which i have to carrry when i enter in casino.

srikant kumar sahu

accountant

24 Points Joined August 2011

I have to carry $11.25 /- when i enter into the casino

the problem is splved in this way

[{(x-5)X2}-10] X 2 -5 =0

[{(x-5)X2}-10] = 2.5

{(x-5)X2} = 12.5

(x-5) = 6.25

x = 6.25 + 5

x = 11.25

CA,CMA,CS Karan Gogia

Employed

230 Points Joined July 2009

shortand simple...

he has to pay

entry to gate 1=5 ....double... exit =5

entry to gate 2=5 ....double... exit =5

entry to gate 3=5 ....double... exit =5

entry to gate 4=5 ....double... exit =5

the ans is 14.0625...attached is the excel file ..

v@m$h!

CA - Final and CS - Final

1473 Points Joined December 2008

7.5$

enter A - 5$

doubles 2.5 $ = 5$

come out of B

Enters C pays 5$

balance Nil

doubles "0"

comeout of D Nil money

Vikas

Chartered Accountant

162 Points Joined July 2009

Correct ans is $11.25.

Gate A pays $5 and left with $6.25. Inside doubles and get $12.5. Then exits at Gate B pays $5 and left with $7.5. Then enter from Gate C and pays $5 and left with $2.5. Inside double and get $5 and while finally exits at Gate D pays $5 and left with no money.