in a frequency distribution,the mid value of class is 15 & the class interval length is 4.the lower limit of class is
a).13 b).14
c).12 d).11
in a frequency distribution,the mid value of class is 15 & the class interval length is 4.the lower limit of class is
a).13 b).14
c).12 d).11
If the interval is 13-17 the length of the intervalis 4 and midpoint is 15
Here is the lengthy solution :
Lower limit = x
Higher limit = y
Now solve these two equations -
(x+y)/2 = 15 , &,
y - x = 4
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