Well frnds…
Is 1=2?? 2=3??
Yes…
How???????
Listen very very carefully…
Be cautious in all moves..
We all no 6 = 6
And so -6 = -6
Lets expand it 9 - 15 = 4 - 10
Any doubts?????
Okay…
Still more expanding (3*3) - (3*5) = (2*2) - (2*5)
Its so simple.. Lets make it complex.
Why not add something to it (3*3) + (25/4) - (3*5) = (2*2) + (25/4) - (2*5)
Why not multiply something to it (3*3) + (25/4) - (2/2*3*5) = (2*2) + (25/4) - (2/2*2*5)
Mm.. not bad….
But in CA we shud always explain
every step in detail..
den only step marks..
So…Still more expand (3*3)+(5/2*5/2) -( 2/2*3*5) = (2*2)+(5/2*5/2)-( 2/2*2*5)
Slight modification watch keenly (3*3)+(5/2*5/2) -(2*3*5/2) = (2*2)+(5/2*5/2)-(2*2*5/2)
Mmmm…
Nice moves na..
Now
Raise ur hands
How many of u no algebra
???????????????
Well
Let me teach once again
(a+b)(a+b)= a*a + b*b +2ab
(a-b)(a-b) =a*a + b*b -2ab
Applying d same (3*3)+(5/2*5/2)-(2)*(3*5/2) =(2*2)+ (5/2*5/2)-(2)*(2*5/2)
Finally (3-5/2) (3-5/2) = (2-5/2) (2-5/2)
Den (3-5/2)^2= (2-5/2)^2
Taking square root on both sides (3-5/2)= (2-5/2)
Canceling 5/2 on both sides 3=2
Wat????????
Hey hey wait wait……
Somwer u did som tricks……..
Let me check once again……..
Tanq everyone for checking ma answer..
!!!!!!!!!!!!!!!!!!!!!
KARTHIK.E.
That is a good one, but to defend it wrong i have a answer
(3-5/2)^2=(2-5/2)^2
(3-5/2)=square root of((2-5/2)^2))
now you will get two answers
3-5/2=2-5/2
so you say 3=2 (which is absurd)
now the second answer is 3-5/2=-(2-5/2)
so 3+2=5/2+5/2
so 5=5
that is what mathematically right
any ways good effort keep posting.....
Den (3-5/2)^2= (2-5/2)^2
Taking square root on both sides (3-5/2)= (2-5/2)
Canceling 5/2 on both sides 3=2
Wat????????
Hey hey wait wait……
-----
You are wrong here:
When you take square root of something it is always expressed as + or - and thus the operational notator is missed here. And thus 1/2 = 1/2 comes and thus there is no discrepancy.This is an old mathematical puzzle which we had in School,nothing great about it.Maybe those who dotn know maths might find it strange.Go and ask a Math prof,he will tell you what I mean!!