given that:
log 2 X (ie log x to the base 2) + log 4 X +log 16 X = 21/4 then x =??
answr as per icai module is 8 bt i dont know how to solve...
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Cpt - qa qstn ... plz help
Replies (2)
You know the formula, Log an pm= m/n logap
Applying the formula,
Log2x + 1/2 Log2x + 1/4 Log2x = 21/4
Taking Log2x common,
(1 + 1/2 + 1/4) Log2x = 21/4
(7/4) Log2x = 21/4
Log2x = 3
X =23 = 8
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