Can you solve this???? series

S, S

well done .. rupeshji

can you please solve this 1,2,3,5,6,7,10,11,12,13.......... what is the 302nd term?

This is simple question based on A.P series a+(n-1)d 

here a=1, n=302, d=1

hence nth term = 1+(302-1)d

            nth term  =302

sorry Dheeraj, u have missed....actually in the series perfect squares and perfect cubes are missing.....in that case what wil be the ans

291th term

total missing number is :

4, 8, 9, 16, 27, 32, 64, 81, 128, 243, 256 = 11

302 - 11 = 291

i think this is the only way to do...but it is tedious. actuallly there more than 11 like 25,36,49,100,121...

actually i got this question in an apti exam