 
			 
              
                
                Accounts-Executive
                
                   196 Points
                   Joined October 2010
                
               
			  
			  
             
            
             
	To Dhanshree ,
	    i would like to give few info. on this question before  further solving :-
	1 . This question is already asked in CWA- JUNE 2007 for 8 marks.
	2.  ur info in above question is wrong realted to Z Area of  0.6 . The correct proability i.e 0.6 = 0.2743
	3.  ur d1 value is also wrong . The correct value of d1 after solving is d1 = 0.58168.
	calculation of  N(d1)  = N(.58168) = ?
	answer shown below :-
	given table value for (Z = 0.55) = .2912    
	                                     (Z = 0.60) = .2743
	N(0.55) = 1- 0.2912 = .7088 (Refer explanation no. 1)
	N(0.60) = 1- 0.2743 = .7257 (Refer explanation no. 1)
	Explanation No. 1
	as we know that total probability of table is 1 & in "one tail table" if z = +ve then it shows right side area probability of calculated  Z (use right tail table).
	now use interpolation technique in figures given below :-
	.55       = 0.7088
	.58168 = ?
	.60        = .07257
	from calculation using interpolation technique ,
	we got value of N(d1) i.e. N(.58168) = 0.7195.
	so , Dhanshree ur query has been solved out .. hope that further part of question will be done by your self ..
	 
	Thanks
	J_Laphadi