1).if f(x) = x+1,.g(x) = x^2+1 fog (-2) =?
ans: 6.
2).if f(x-1) = x^2-4x+8 then f(x+1) = ?
ans : x^2+4
3).the value of 2logx+2logx^2+2logx^3 -----------------------nlogx^n =
ans: n(n+1)logx.
4).the recurring decimal 2.777 -----------is expressed as
ans: 25/9.
5).one root of x^2-3x+k = 0 is 2 then k is
ans: 2.
6).the value of k for which the roots of the equation 12x^2+kx+5 = 0 in the ratio 3:2.
ans: 5.10^1/2.
Finally What do you want to Express Mam !!
Could't find anything to solve !!
what is this?????????????????
isse kahte h attempt ka pressure "kya question hai...... lagta hi nahi ki question h.... 
for 1.f(x)=x+1,g(x)=x^2+1
so, f(g(x))=f(x^2+1)
=x^2+1+1
=x^2+2
now,f(-2)=(-2)^2+2(substituting x= -2 )
=4+2=6
for2.
2logx + 2log x^2 + 2logx^3+..........+nlogx^n
=2logx + 2.2logx + 2.3logx+.......+n.nlogx(by formula logx^n=nlogx)
=2logx(1+2+3+.....+n) ( taking out 2logx as common)
=2logx.n(n+1)/2 ( 1+2+3+....+n=n(n+1)/2)
=n(n+1)logx
if u r facing problem in maths u can refer maths books of 11th and 12th science group of any of ur science group friends .it will surely help..
BANSAL YOGESH AND CO
Gautam Budh Nagar
B.Com
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