Qa - poisson distribution

Please help me with these.

A car hire firm has 2 cars which is hired out every day. The number of demands for a car on each day follows Poisson distribution with mean 1.20. What is the proportion of days on which some demand is refused? [ Given e^1.2 = 3.32]
a) 0.25    b) 0.3012   c) 0.12    d) 0.03

The number of accidents in a year is attributed to taxi drivers in a locality follows poisson distribution with an average 2. Out of 500 taxi drivers of that area, what is the number of drivers  with at least 3 accidents in a year?
a) 162    b) 180         c) 201     d) 190

FIRST Answer is 0.12

and second answer is 162

first one refusing the demand means,morethan two cars are demanded.

P(x>2) = 1 - P(x=0)+P(x=1)+P(x=2)

                1 - (0.3012+0.36144+0.216864)

                1- 0.879504

                0.120496   = 0.12

second one @ least 3 accidents 

P(x @ least3) = 1 - P(x=0)+P(x=1)+P(x=2)

                          1 - 0.1353+0.2706+0.2706

                          1 - 0.6765

                          0.3235

the number of taxidrivers with @ least 3 accidents is 

N * P(x @ least3)

500 * 0.3235

161.75