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# Qa - poisson distribution

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 priya Student [ Scorecard : 64] Posted On 03 June 2012 at 19:57 Please help me with these. A car hire firm has 2 cars which is hired out every day. The number of demands for a car on each day follows Poisson distribution with mean 1.20. What is the proportion of days on which some demand is refused? [ Given e^1.2 = 3.32] a) 0.25    b) 0.3012   c) 0.12    d) 0.03 The number of accidents in a year is attributed to taxi drivers in a locality follows poisson distribution with an average 2. Out of 500 taxi drivers of that area, what is the number of drivers  with at least 3 accidents in a year? a) 162    b) 180         c) 201     d) 190 purushottam students [ Scorecard : 31] Posted On 03 June 2012 at 20:10 FIRST Answer is 0.12 and second answer is 162 purushottam students [ Scorecard : 31] Posted On 03 June 2012 at 20:35 first one refusing the demand means,morethan two cars are demanded. P(x>2) = 1 - P(x=0)+P(x=1)+P(x=2)                 1 - (0.3012+0.36144+0.216864)                 1- 0.879504                 0.120496   = 0.12 second one @ least 3 accidents  P(x @ least3) = 1 - P(x=0)+P(x=1)+P(x=2)                           1 - 0.1353+0.2706+0.2706                           1 - 0.6765                           0.3235 the number of taxidrivers with @ least 3 accidents is  N * P(x @ least3) 500 * 0.3235 161.75   Total thanks : 1 times

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